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55631413000 = 2353106152433
BaseRepresentation
bin110011110011111000…
…111111111100001000
312022121001022120222201
4303303320333330020
51402413120204000
641320130125544
74006412131312
oct636370777410
9168531276881
1055631413000
1121658533a89
12a946a208b4
135327675377
14299a5d47b2
1516a8e7196a
hexcf3e3ff08

55631413000 has 64 divisors (see below), whose sum is σ = 130302684720. Its totient is φ = 22231168000.

The previous prime is 55631412989. The next prime is 55631413009. The reversal of 55631413000 is 31413655.

It can be written as a sum of positive squares in 8 ways, for example, as 9421031844 + 46210381156 = 97062^2 + 214966^2 .

It is a super-2 number, since 2×556314130002 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 55631413000.

It is not an unprimeable number, because it can be changed into a prime (55631413009) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1034784 + ... + 1087216.

Almost surely, 255631413000 is an apocalyptic number.

55631413000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 55631413000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (65151342360).

55631413000 is an abundant number, since it is smaller than the sum of its proper divisors (74671271720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

55631413000 is a wasteful number, since it uses less digits than its factorization.

55631413000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53515 (or 53501 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 55631413000 its reverse (31413655), we get a palindrome (55662826655).

The spelling of 55631413000 in words is "fifty-five billion, six hundred thirty-one million, four hundred thirteen thousand".

Divisors: 1 2 4 5 8 10 20 25 40 50 100 125 200 250 500 1000 1061 2122 4244 5305 8488 10610 21220 26525 42440 52433 53050 104866 106100 132625 209732 212200 262165 265250 419464 524330 530500 1048660 1061000 1310825 2097320 2621650 5243300 6554125 10486600 13108250 26216500 52433000 55631413 111262826 222525652 278157065 445051304 556314130 1112628260 1390785325 2225256520 2781570650 5563141300 6953926625 11126282600 13907853250 27815706500 55631413000