Base | Representation |
---|---|
bin | 11001011110111001101111… |
… | …01111001111000001000110 |
3 | 21100102010020220102021200011 |
4 | 30233130313233033001012 |
5 | 24321104020100040240 |
6 | 315103114114540434 |
7 | 14542365232062061 |
oct | 1457346757170106 |
9 | 240363226367604 |
10 | 56037373440070 |
11 | 169453534631a0 |
12 | 6350502b9771a |
13 | 25363bc923149 |
14 | dba31ac0b8d8 |
15 | 6729d9c046ea |
hex | 32f737bcf046 |
56037373440070 has 32 divisors (see below), whose sum is σ = 116509790343456. Its totient is φ = 19178566310400.
The previous prime is 56037373440011. The next prime is 56037373440101. The reversal of 56037373440070 is 7004437373065.
It is a super-3 number, since 3×560373734400703 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 56037373439996 and 56037373440023.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14983253061 + ... + 14983256800.
It is an arithmetic number, because the mean of its divisors is an integer number (3640930948233).
Almost surely, 256037373440070 is an apocalyptic number.
56037373440070 is an abundant number, since it is smaller than the sum of its proper divisors (60472416903386).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
56037373440070 is a wasteful number, since it uses less digits than its factorization.
56037373440070 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29966509896.
The product of its (nonzero) digits is 4445280, while the sum is 49.
The spelling of 56037373440070 in words is "fifty-six trillion, thirty-seven billion, three hundred seventy-three million, four hundred forty thousand, seventy".
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