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5614330434149 is a prime number
BaseRepresentation
bin101000110110011000000…
…1010111101001001100101
3201212201120100012122220202
41101230300022331021211
51213441122042343044
615535104321440245
71116423225202433
oct121546012751145
921781510178822
105614330434149
11187502a18a368
12768117aa0085
13319576925bb8
14155a40d59d53
159b0956e3c4e
hex51b302bd265

5614330434149 has 2 divisors, whose sum is σ = 5614330434150. Its totient is φ = 5614330434148.

The previous prime is 5614330434137. The next prime is 5614330434151. The reversal of 5614330434149 is 9414340334165.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5546057970049 + 68272464100 = 2355007^2 + 261290^2 .

It is a cyclic number.

It is not a de Polignac number, because 5614330434149 - 220 = 5614329385573 is a prime.

Together with 5614330434151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5614330434169) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2807165217074 + 2807165217075.

It is an arithmetic number, because the mean of its divisors is an integer number (2807165217075).

Almost surely, 25614330434149 is an apocalyptic number.

It is an amenable number.

5614330434149 is a deficient number, since it is larger than the sum of its proper divisors (1).

5614330434149 is an equidigital number, since it uses as much as digits as its factorization.

5614330434149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1866240, while the sum is 47.

The spelling of 5614330434149 in words is "five trillion, six hundred fourteen billion, three hundred thirty million, four hundred thirty-four thousand, one hundred forty-nine".