Base | Representation |
---|---|
bin | 1010101000000111… |
… | …01010010111011111 |
3 | 112201121100212111021 |
4 | 11110003222113133 |
5 | 43141013312112 |
6 | 2342042305011 |
7 | 261244341145 |
oct | 52403522737 |
9 | 15647325437 |
10 | 5705213407 |
11 | 2468498303 |
12 | 11327b8167 |
13 | 6cbca4c2a |
14 | 3c19d5595 |
15 | 235d08907 |
hex | 1540ea5df |
5705213407 has 2 divisors, whose sum is σ = 5705213408. Its totient is φ = 5705213406.
The previous prime is 5705213387. The next prime is 5705213441. The reversal of 5705213407 is 7043125075.
It is an a-pointer prime, because the next prime (5705213441) can be obtained adding 5705213407 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5705213407 - 211 = 5705211359 is a prime.
It is a super-3 number, since 3×57052134073 (a number of 30 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5705213497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2852606703 + 2852606704.
It is an arithmetic number, because the mean of its divisors is an integer number (2852606704).
Almost surely, 25705213407 is an apocalyptic number.
5705213407 is a deficient number, since it is larger than the sum of its proper divisors (1).
5705213407 is an equidigital number, since it uses as much as digits as its factorization.
5705213407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29400, while the sum is 34.
The square root of 5705213407 is about 75532.8630928287. The cubic root of 5705213407 is about 1786.8604294890.
The spelling of 5705213407 in words is "five billion, seven hundred five million, two hundred thirteen thousand, four hundred seven".
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