Base | Representation |
---|---|
bin | 110101010010111001… |
… | …011101111101101111 |
3 | 12110201010122001222211 |
4 | 311102321131331233 |
5 | 1414144143342003 |
6 | 42142230151251 |
7 | 4064045426536 |
oct | 652271357557 |
9 | 173633561884 |
10 | 57225371503 |
11 | 222a6259663 |
12 | b1107b2527 |
13 | 551c974291 |
14 | 2aac19531d |
15 | 174dd7a96d |
hex | d52e5df6f |
57225371503 has 2 divisors, whose sum is σ = 57225371504. Its totient is φ = 57225371502.
The previous prime is 57225371501. The next prime is 57225371543. The reversal of 57225371503 is 30517352275.
It is an a-pointer prime, because the next prime (57225371543) can be obtained adding 57225371503 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 57225371503 - 21 = 57225371501 is a prime.
Together with 57225371501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (57225371501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28612685751 + 28612685752.
It is an arithmetic number, because the mean of its divisors is an integer number (28612685752).
Almost surely, 257225371503 is an apocalyptic number.
57225371503 is a deficient number, since it is larger than the sum of its proper divisors (1).
57225371503 is an equidigital number, since it uses as much as digits as its factorization.
57225371503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 220500, while the sum is 40.
The spelling of 57225371503 in words is "fifty-seven billion, two hundred twenty-five million, three hundred seventy-one thousand, five hundred three".
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