Base | Representation |
---|---|
bin | 1011000101011000… |
… | …01111010010001000 |
3 | 120100201100110212021 |
4 | 11202230033102020 |
5 | 44141341401100 |
6 | 2422252454224 |
7 | 300315245065 |
oct | 54254172210 |
9 | 16321313767 |
10 | 5950731400 |
11 | 258403a639 |
12 | 11a0a7a374 |
13 | 73ab08553 |
14 | 406465c6c |
15 | 24c654a1a |
hex | 162b0f488 |
5950731400 has 24 divisors (see below), whose sum is σ = 13835450970. Its totient is φ = 2380292480.
The previous prime is 5950731379. The next prime is 5950731421. The reversal of 5950731400 is 41370595.
It is an interprime number because it is at equal distance from previous prime (5950731379) and next prime (5950731421).
It can be written as a sum of positive squares in 3 ways, for example, as 5440242564 + 510488836 = 73758^2 + 22594^2 .
It is a super-2 number, since 2×59507314002 = 70822408389891920000, which contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 14876629 + ... + 14877028.
Almost surely, 25950731400 is an apocalyptic number.
5950731400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5950731400 is an abundant number, since it is smaller than the sum of its proper divisors (7884719570).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5950731400 is a wasteful number, since it uses less digits than its factorization.
5950731400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29753673 (or 29753664 counting only the distinct ones).
The product of its (nonzero) digits is 18900, while the sum is 34.
The square root of 5950731400 is about 77140.9839190556. The cubic root of 5950731400 is about 1812.1331950554.
The spelling of 5950731400 in words is "five billion, nine hundred fifty million, seven hundred thirty-one thousand, four hundred".
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