Base | Representation |
---|---|
bin | 111000111010011101… |
… | …010110001000011100 |
3 | 12211201212211120112110 |
4 | 320322131112020130 |
5 | 2000123220013000 |
6 | 44023530034020 |
7 | 4262241044205 |
oct | 707235261034 |
9 | 184655746473 |
10 | 61110313500 |
11 | 23a0a1a7025 |
12 | ba15878910 |
13 | 59bb7ac322 |
14 | 2d5a1185ac |
15 | 18c9e74850 |
hex | e3a75621c |
61110313500 has 48 divisors (see below), whose sum is σ = 177953237280. Its totient is φ = 16296083200.
The previous prime is 61110313469. The next prime is 61110313501. The reversal of 61110313500 is 531301116.
61110313500 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61110313501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20368605 + ... + 20371604.
It is an arithmetic number, because the mean of its divisors is an integer number (3707359110).
Almost surely, 261110313500 is an apocalyptic number.
61110313500 is a gapful number since it is divisible by the number (60) formed by its first and last digit.
It is an amenable number.
61110313500 is an abundant number, since it is smaller than the sum of its proper divisors (116842923780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
61110313500 is a wasteful number, since it uses less digits than its factorization.
61110313500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40740231 (or 40740219 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 21.
Adding to 61110313500 its reverse (531301116), we get a palindrome (61641614616).
The spelling of 61110313500 in words is "sixty-one billion, one hundred ten million, three hundred thirteen thousand, five hundred".
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