Search a number
-
+
611402973941 is a prime number
BaseRepresentation
bin10001110010110100111…
…01010000001011110101
32011110010201120011001102
420321122131100023311
540004123130131231
61144512531335445
762113064350004
oct10713235201365
92143121504042
10611402973941
11216327048701
129a5b1751585
13458691c7c76
1421840890c3b
1510d85eabacb
hex8e5a7502f5

611402973941 has 2 divisors, whose sum is σ = 611402973942. Its totient is φ = 611402973940.

The previous prime is 611402973893. The next prime is 611402973943. The reversal of 611402973941 is 149379204116.

611402973941 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 391187702500 + 220215271441 = 625450^2 + 469271^2 .

It is a cyclic number.

It is not a de Polignac number, because 611402973941 - 26 = 611402973877 is a prime.

Together with 611402973943, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (611402973943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 305701486970 + 305701486971.

It is an arithmetic number, because the mean of its divisors is an integer number (305701486971).

Almost surely, 2611402973941 is an apocalyptic number.

It is an amenable number.

611402973941 is a deficient number, since it is larger than the sum of its proper divisors (1).

611402973941 is an equidigital number, since it uses as much as digits as its factorization.

611402973941 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 326592, while the sum is 47.

The spelling of 611402973941 in words is "six hundred eleven billion, four hundred two million, nine hundred seventy-three thousand, nine hundred forty-one".