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6116716730351 is a prime number
BaseRepresentation
bin101100100000010100010…
…1110100101011111101111
3210122202022111122210011002
41121000220232211133233
51300204013440332401
621001551511350515
71200626641231643
oct131005056453757
923582274583132
106116716730351
111a490a314a487
1282956408243b
13354a5b271c56
1417209d072c23
15a919aa92a6b
hex59028ba57ef

6116716730351 has 2 divisors, whose sum is σ = 6116716730352. Its totient is φ = 6116716730350.

The previous prime is 6116716730323. The next prime is 6116716730353. The reversal of 6116716730351 is 1530376176116.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 6116716730351 - 222 = 6116712536047 is a prime.

Together with 6116716730353, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 6116716730296 and 6116716730305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6116716730353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3058358365175 + 3058358365176.

It is an arithmetic number, because the mean of its divisors is an integer number (3058358365176).

Almost surely, 26116716730351 is an apocalyptic number.

6116716730351 is a deficient number, since it is larger than the sum of its proper divisors (1).

6116716730351 is an equidigital number, since it uses as much as digits as its factorization.

6116716730351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 476280, while the sum is 47.

The spelling of 6116716730351 in words is "six trillion, one hundred sixteen billion, seven hundred sixteen million, seven hundred thirty thousand, three hundred fifty-one".