Base | Representation |
---|---|
bin | 111001000100101001… |
… | …101001101011010111 |
3 | 12212011210121011121202 |
4 | 321010221221223113 |
5 | 2001001003431242 |
6 | 44052515103115 |
7 | 4266415360406 |
oct | 710451515327 |
9 | 185153534552 |
10 | 61281311447 |
11 | 23a97780344 |
12 | ba62ba1a9b |
13 | 5a18050945 |
14 | 2d74b0b63d |
15 | 18d9ea0932 |
hex | e44a69ad7 |
61281311447 has 2 divisors, whose sum is σ = 61281311448. Its totient is φ = 61281311446.
The previous prime is 61281311431. The next prime is 61281311449. The reversal of 61281311447 is 74411318216.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61281311447 - 24 = 61281311431 is a prime.
Together with 61281311449, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 61281311447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61281311449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30640655723 + 30640655724.
It is an arithmetic number, because the mean of its divisors is an integer number (30640655724).
Almost surely, 261281311447 is an apocalyptic number.
61281311447 is a deficient number, since it is larger than the sum of its proper divisors (1).
61281311447 is an equidigital number, since it uses as much as digits as its factorization.
61281311447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 32256, while the sum is 38.
The spelling of 61281311447 in words is "sixty-one billion, two hundred eighty-one million, three hundred eleven thousand, four hundred forty-seven".
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