Base | Representation |
---|---|
bin | 111001001100000001… |
… | …100000011010010111 |
3 | 12212111102100110220121 |
4 | 321030001200122113 |
5 | 2001224140133323 |
6 | 44113054212411 |
7 | 4302446635354 |
oct | 711401403227 |
9 | 185442313817 |
10 | 61405005463 |
11 | 240505854aa |
12 | ba984b4107 |
13 | 5a3786c079 |
14 | 2d8730962b |
15 | 18e5c85a5d |
hex | e4c060697 |
61405005463 has 2 divisors, whose sum is σ = 61405005464. Its totient is φ = 61405005462.
The previous prime is 61405005461. The next prime is 61405005517. The reversal of 61405005463 is 36450050416.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 61405005463 - 21 = 61405005461 is a prime.
It is a super-2 number, since 2×614050054632 (a number of 22 digits) contains 22 as substring.
Together with 61405005461, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (61405005461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30702502731 + 30702502732.
It is an arithmetic number, because the mean of its divisors is an integer number (30702502732).
Almost surely, 261405005463 is an apocalyptic number.
61405005463 is a deficient number, since it is larger than the sum of its proper divisors (1).
61405005463 is an equidigital number, since it uses as much as digits as its factorization.
61405005463 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 61405005463 its reverse (36450050416), we get a palindrome (97855055879).
The spelling of 61405005463 in words is "sixty-one billion, four hundred five million, five thousand, four hundred sixty-three".
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