Base | Representation |
---|---|
bin | 1000111000100000110000011… |
… | …1101001101010000110011111 |
3 | 10000222020120121110001202110101 |
4 | 2032020030013221222012133 |
5 | 1123412344321123402112 |
6 | 10053240131212521531 |
7 | 245443633164163642 |
oct | 21610140751520637 |
9 | 3028216543052411 |
10 | 625085373653407 |
11 | 171198244537997 |
12 | 5a135896a802a7 |
13 | 20aa33b43937a4 |
14 | b050417575a59 |
15 | 4c3ed898a7757 |
hex | 2388307a6a19f |
625085373653407 has 2 divisors, whose sum is σ = 625085373653408. Its totient is φ = 625085373653406.
The previous prime is 625085373653387. The next prime is 625085373653441. The reversal of 625085373653407 is 704356373580526.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 625085373653407 - 211 = 625085373651359 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (625085373653107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 312542686826703 + 312542686826704.
It is an arithmetic number, because the mean of its divisors is an integer number (312542686826704).
Almost surely, 2625085373653407 is an apocalyptic number.
625085373653407 is a deficient number, since it is larger than the sum of its proper divisors (1).
625085373653407 is an equidigital number, since it uses as much as digits as its factorization.
625085373653407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 381024000, while the sum is 64.
The spelling of 625085373653407 in words is "six hundred twenty-five trillion, eighty-five billion, three hundred seventy-three million, six hundred fifty-three thousand, four hundred seven".
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