63145035407 has 2 divisors, whose sum is σ = 63145035408. Its totient is φ = 63145035406.

The previous prime is 63145035403. The next prime is 63145035409. The reversal of 63145035407 is 70453054136.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 63145035407 - 2² = 63145035403 is a prime.

It is a super-3 number, since 3×63145035407³ (a number of 33 digits) contains 333 as substring.

Together with 63145035409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (63145035403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 31572517703 + 31572517704.

It is an arithmetic number, because the mean of its divisors is an integer number (31572517704).

Almost surely, 2^63145035407 is an apocalyptic number.

63145035407 is a deficient number, since it is larger than the sum of its proper divisors (1).

63145035407 is an equidigital number, since it uses as much as digits as its factorization.

63145035407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 38.

The spelling of 63145035407 in words is "sixty-three billion, one hundred forty-five million, thirty-five thousand, four hundred seven".