Base | Representation |
---|---|
bin | 10010101010101100000… |
… | …10111111111110111111 |
3 | 2021022112211111122002222 |
4 | 21111112002333332333 |
5 | 41002033300112142 |
6 | 1210352514035555 |
7 | 64224222645464 |
oct | 11252602777677 |
9 | 2238484448088 |
10 | 641393754047 |
11 | 228017064692 |
12 | a4381578bbb |
13 | 486386b25b7 |
14 | 230879b966b |
15 | 11a3ddb3bd2 |
hex | 95560bffbf |
641393754047 has 2 divisors, whose sum is σ = 641393754048. Its totient is φ = 641393754046.
The previous prime is 641393753989. The next prime is 641393754049. The reversal of 641393754047 is 740457393146.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 641393754047 - 216 = 641393688511 is a prime.
It is a super-2 number, since 2×6413937540472 (a number of 24 digits) contains 22 as substring.
Together with 641393754049, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 641393754047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (641393754049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 320696877023 + 320696877024.
It is an arithmetic number, because the mean of its divisors is an integer number (320696877024).
Almost surely, 2641393754047 is an apocalyptic number.
641393754047 is a deficient number, since it is larger than the sum of its proper divisors (1).
641393754047 is an equidigital number, since it uses as much as digits as its factorization.
641393754047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7620480, while the sum is 53.
The spelling of 641393754047 in words is "six hundred forty-one billion, three hundred ninety-three million, seven hundred fifty-four thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •