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645322440013 is a prime number
BaseRepresentation
bin10010110010000000011…
…01101111110101001101
32021200200122000120002121
421121000031233311031
541033110021040023
61212242415252541
764423456143436
oct11310015576515
92250618016077
10645322440013
1122975276a599
12a509921a151
1348b135c5354
142333b68848d
1511bbdc4dd5d
hex964036fd4d

645322440013 has 2 divisors, whose sum is σ = 645322440014. Its totient is φ = 645322440012.

The previous prime is 645322440011. The next prime is 645322440053. The reversal of 645322440013 is 310044223546.

645322440013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 610489070244 + 34833369769 = 781338^2 + 186637^2 .

It is a cyclic number.

It is not a de Polignac number, because 645322440013 - 21 = 645322440011 is a prime.

Together with 645322440011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (645322440011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 322661220006 + 322661220007.

It is an arithmetic number, because the mean of its divisors is an integer number (322661220007).

Almost surely, 2645322440013 is an apocalyptic number.

It is an amenable number.

645322440013 is a deficient number, since it is larger than the sum of its proper divisors (1).

645322440013 is an equidigital number, since it uses as much as digits as its factorization.

645322440013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 645322440013 its reverse (310044223546), we get a palindrome (955366663559).

The spelling of 645322440013 in words is "six hundred forty-five billion, three hundred twenty-two million, four hundred forty thousand, thirteen".