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649704953 is a prime number
BaseRepresentation
bin100110101110011…
…011010111111001
31200021112102122102
4212232123113321
52312311024303
6144245233145
722046254352
oct4656332771
91607472572
10649704953
11303817a47
121617027b5
13a47ac901
1462404d29
153c08a288
hex26b9b5f9

649704953 has 2 divisors, whose sum is σ = 649704954. Its totient is φ = 649704952.

The previous prime is 649704947. The next prime is 649704959. The reversal of 649704953 is 359407946.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (649704947) and next prime (649704959).

It can be written as a sum of positive squares in only one way, i.e., 593799424 + 55905529 = 24368^2 + 7477^2 .

It is a cyclic number.

It is not a de Polignac number, because 649704953 - 28 = 649704697 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 649704898 and 649704907.

It is not a weakly prime, because it can be changed into another prime (649704959) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 324852476 + 324852477.

It is an arithmetic number, because the mean of its divisors is an integer number (324852477).

Almost surely, 2649704953 is an apocalyptic number.

It is an amenable number.

649704953 is a deficient number, since it is larger than the sum of its proper divisors (1).

649704953 is an equidigital number, since it uses as much as digits as its factorization.

649704953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 816480, while the sum is 47.

The square root of 649704953 is about 25489.3105634499. The cubic root of 649704953 is about 866.1080181973.

The spelling of 649704953 in words is "six hundred forty-nine million, seven hundred four thousand, nine hundred fifty-three".