Search a number
-
+
6561768944053 is a prime number
BaseRepresentation
bin101111101111100011111…
…1010000011000110110101
3212020022001221220201221101
41133133013322003012311
51330002000322202203
621542233545050101
71245033515515531
oct137370772030665
925208057821841
106561768944053
1120aa91555a844
1289b86b186931
13387a065732bb
1418983c7b6bc1
15b5a4779041d
hex5f7c7e831b5

6561768944053 has 2 divisors, whose sum is σ = 6561768944054. Its totient is φ = 6561768944052.

The previous prime is 6561768944011. The next prime is 6561768944117. The reversal of 6561768944053 is 3504498671656.

It is an a-pointer prime, because the next prime (6561768944117) can be obtained adding 6561768944053 to its sum of digits (64).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6561087577444 + 681366609 = 2561462^2 + 26103^2 .

It is a cyclic number.

It is not a de Polignac number, because 6561768944053 - 213 = 6561768935861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (6561768947053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3280884472026 + 3280884472027.

It is an arithmetic number, because the mean of its divisors is an integer number (3280884472027).

Almost surely, 26561768944053 is an apocalyptic number.

It is an amenable number.

6561768944053 is a deficient number, since it is larger than the sum of its proper divisors (1).

6561768944053 is an equidigital number, since it uses as much as digits as its factorization.

6561768944053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 130636800, while the sum is 64.

The spelling of 6561768944053 in words is "six trillion, five hundred sixty-one billion, seven hundred sixty-eight million, nine hundred forty-four thousand, fifty-three".