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680251307 is a prime number
BaseRepresentation
bin101000100010111…
…100111110101011
31202102000100100212
4220202330332223
52343121020212
6151300051335
722600016651
oct5042747653
91672010325
10680251307
11319a9096a
1216b993b4b
13aac16488
14664b6dd1
153eac0e22
hex288bcfab

680251307 has 2 divisors, whose sum is σ = 680251308. Its totient is φ = 680251306.

The previous prime is 680251301. The next prime is 680251309. The reversal of 680251307 is 703152086.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 680251307 - 24 = 680251291 is a prime.

It is a super-4 number, since 4×6802513074 (a number of 36 digits) contains 4444 as substring.

Together with 680251309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (680251301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 340125653 + 340125654.

It is an arithmetic number, because the mean of its divisors is an integer number (340125654).

Almost surely, 2680251307 is an apocalyptic number.

680251307 is a deficient number, since it is larger than the sum of its proper divisors (1).

680251307 is an equidigital number, since it uses as much as digits as its factorization.

680251307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10080, while the sum is 32.

The square root of 680251307 is about 26081.6277674535. The cubic root of 680251307 is about 879.4742499202.

The spelling of 680251307 in words is "six hundred eighty million, two hundred fifty-one thousand, three hundred seven".