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681275410199 is a prime number
BaseRepresentation
bin10011110100111110010…
…11011100011100010111
32102010111020212200100222
421322133023130130113
542130223001111244
61240550144224555
7100135432303466
oct11723713343427
92363436780328
10681275410199
11242a2223219a
12b005190b15b
134c32309a9c7
1424d8c57c9dd
1512ac52c0bee
hex9e9f2dc717

681275410199 has 2 divisors, whose sum is σ = 681275410200. Its totient is φ = 681275410198.

The previous prime is 681275410187. The next prime is 681275410201. The reversal of 681275410199 is 991014572186.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 681275410199 - 232 = 676980442903 is a prime.

Together with 681275410201, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 681275410199.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (681275400199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 340637705099 + 340637705100.

It is an arithmetic number, because the mean of its divisors is an integer number (340637705100).

Almost surely, 2681275410199 is an apocalyptic number.

681275410199 is a deficient number, since it is larger than the sum of its proper divisors (1).

681275410199 is an equidigital number, since it uses as much as digits as its factorization.

681275410199 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 53.

The spelling of 681275410199 in words is "six hundred eighty-one billion, two hundred seventy-five million, four hundred ten thousand, one hundred ninety-nine".