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68313103 is a prime number
BaseRepresentation
bin1000001001001…
…10000000001111
311202112122221221
410010212000033
5114442004403
610440104211
71456436365
oct404460017
9152478857
1068313103
1135619711
121aa65067
13111caa71
149103635
155ee5dbd
hex412600f

68313103 has 2 divisors, whose sum is σ = 68313104. Its totient is φ = 68313102.

The previous prime is 68313083. The next prime is 68313109. The reversal of 68313103 is 30131386.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 68313103 - 25 = 68313071 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (68313109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34156551 + 34156552.

It is an arithmetic number, because the mean of its divisors is an integer number (34156552).

Almost surely, 268313103 is an apocalyptic number.

68313103 is a deficient number, since it is larger than the sum of its proper divisors (1).

68313103 is an equidigital number, since it uses as much as digits as its factorization.

68313103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

The square root of 68313103 is about 8265.1741058492. The cubic root of 68313103 is about 408.7910111694.

Adding to 68313103 its reverse (30131386), we get a palindrome (98444489).

The spelling of 68313103 in words is "sixty-eight million, three hundred thirteen thousand, one hundred three".