Base | Representation |
---|---|
bin | 100010001010111010… |
… | …0001101111000110101 |
3 | 21000102000021021220102 |
4 | 1010111310031320311 |
5 | 2200240344011231 |
6 | 53413245443445 |
7 | 5205302365334 |
oct | 1042564157065 |
9 | 230360237812 |
10 | 73380453941 |
11 | 29136398163 |
12 | 1227ab70585 |
13 | 6bc58b8862 |
14 | 37a1975d1b |
15 | 1d972a6acb |
hex | 1115d0de35 |
73380453941 has 2 divisors, whose sum is σ = 73380453942. Its totient is φ = 73380453940.
The previous prime is 73380453917. The next prime is 73380453943. The reversal of 73380453941 is 14935408337.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44089500625 + 29290953316 = 209975^2 + 171146^2 .
It is a cyclic number.
It is not a de Polignac number, because 73380453941 - 26 = 73380453877 is a prime.
Together with 73380453943, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (73380453943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36690226970 + 36690226971.
It is an arithmetic number, because the mean of its divisors is an integer number (36690226971).
Almost surely, 273380453941 is an apocalyptic number.
It is an amenable number.
73380453941 is a deficient number, since it is larger than the sum of its proper divisors (1).
73380453941 is an equidigital number, since it uses as much as digits as its factorization.
73380453941 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1088640, while the sum is 47.
The spelling of 73380453941 in words is "seventy-three billion, three hundred eighty million, four hundred fifty-three thousand, nine hundred forty-one".
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