Base | Representation |
---|---|
bin | 10000111110010111010111… |
… | …011000101101100010111111 |
3 | 100210022220011021220202021102 |
4 | 100332113113120231202333 |
5 | 34241114243134314411 |
6 | 422435435405123315 |
7 | 21503414423113223 |
oct | 2076272730554277 |
9 | 323286137822242 |
10 | 74654440151231 |
11 | 21872852256706 |
12 | 8458644b5953b |
13 | 3286b6407cc75 |
14 | 1461419346783 |
15 | 896deedcdd3b |
hex | 43e5d762d8bf |
74654440151231 has 2 divisors, whose sum is σ = 74654440151232. Its totient is φ = 74654440151230.
The previous prime is 74654440151189. The next prime is 74654440151233. The reversal of 74654440151231 is 13215104445647.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-74654440151231 is a prime.
It is a super-2 number, since 2×746544401512312 (a number of 29 digits) contains 22 as substring.
Together with 74654440151233, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (74654440151233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37327220075615 + 37327220075616.
It is an arithmetic number, because the mean of its divisors is an integer number (37327220075616).
Almost surely, 274654440151231 is an apocalyptic number.
74654440151231 is a deficient number, since it is larger than the sum of its proper divisors (1).
74654440151231 is an equidigital number, since it uses as much as digits as its factorization.
74654440151231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1612800, while the sum is 47.
Adding to 74654440151231 its reverse (13215104445647), we get a palindrome (87869544596878).
The spelling of 74654440151231 in words is "seventy-four trillion, six hundred fifty-four billion, four hundred forty million, one hundred fifty-one thousand, two hundred thirty-one".
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