Search a number
-
+
766680132431 is a prime number
BaseRepresentation
bin10110010100000011011…
…00100110101101001111
32201021221020221002110102
423022001230212231033
5100030130103214211
61344112532001315
7106251022412663
oct13120154465517
92637836832412
10766680132431
11276168a47064
1210470776023b
13573b3b671c5
142917104c8a3
1514e22edda3b
hexb281b26b4f

766680132431 has 2 divisors, whose sum is σ = 766680132432. Its totient is φ = 766680132430.

The previous prime is 766680132409. The next prime is 766680132433. The reversal of 766680132431 is 134231086667.

766680132431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 766680132431 - 218 = 766679870287 is a prime.

It is a super-3 number, since 3×7666801324313 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 766680132433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (766680132433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 383340066215 + 383340066216.

It is an arithmetic number, because the mean of its divisors is an integer number (383340066216).

Almost surely, 2766680132431 is an apocalyptic number.

766680132431 is a deficient number, since it is larger than the sum of its proper divisors (1).

766680132431 is an equidigital number, since it uses as much as digits as its factorization.

766680132431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 870912, while the sum is 47.

The spelling of 766680132431 in words is "seven hundred sixty-six billion, six hundred eighty million, one hundred thirty-two thousand, four hundred thirty-one".