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7964736413 is a prime number
BaseRepresentation
bin1110110101011110…
…00011101110011101
3202120002001112100112
413122233003232131
5112302433031123
63354155535405
7401242066604
oct73257035635
922502045315
107964736413
113417982397
12166345a565
1399c1473aa
14557b28a3b
15319381d78
hex1dabc3b9d

7964736413 has 2 divisors, whose sum is σ = 7964736414. Its totient is φ = 7964736412.

The previous prime is 7964736391. The next prime is 7964736463. The reversal of 7964736413 is 3146374697.

It is a happy number.

It is an a-pointer prime, because the next prime (7964736463) can be obtained adding 7964736413 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4539794884 + 3424941529 = 67378^2 + 58523^2 .

It is a cyclic number.

It is not a de Polignac number, because 7964736413 - 224 = 7947959197 is a prime.

It is a super-2 number, since 2×79647364132 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (7964736463) by changing a digit.

It is an upside-down number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3982368206 + 3982368207.

It is an arithmetic number, because the mean of its divisors is an integer number (3982368207).

Almost surely, 27964736413 is an apocalyptic number.

It is an amenable number.

7964736413 is a deficient number, since it is larger than the sum of its proper divisors (1).

7964736413 is an equidigital number, since it uses as much as digits as its factorization.

7964736413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2286144, while the sum is 50.

The square root of 7964736413 is about 89245.3719416307. The cubic root of 7964736413 is about 1997.0570393654.

The spelling of 7964736413 in words is "seven billion, nine hundred sixty-four million, seven hundred thirty-six thousand, four hundred thirteen".