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8082992807 is a prime number
BaseRepresentation
bin1111000011100100…
…01010111010100111
3202212022120120121222
413201302022322213
5113023221232212
63414022330555
7404206206461
oct74162127247
922768516558
108082992807
11347870314a
121696b89a5b
139ba7b07a6
1456970d131
15324940c72
hex1e1c8aea7

8082992807 has 2 divisors, whose sum is σ = 8082992808. Its totient is φ = 8082992806.

The previous prime is 8082992803. The next prime is 8082992809. The reversal of 8082992807 is 7082992808.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 8082992807 - 22 = 8082992803 is a prime.

Together with 8082992809, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (8082992803) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4041496403 + 4041496404.

It is an arithmetic number, because the mean of its divisors is an integer number (4041496404).

Almost surely, 28082992807 is an apocalyptic number.

8082992807 is a deficient number, since it is larger than the sum of its proper divisors (1).

8082992807 is an equidigital number, since it uses as much as digits as its factorization.

8082992807 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1161216, while the sum is 53.

The square root of 8082992807 is about 89905.4659461815. The cubic root of 8082992807 is about 2006.8922881480.

Subtracting from 8082992807 its reverse (7082992808), we obtain a palindrome (999999999).

The spelling of 8082992807 in words is "eight billion, eighty-two million, nine hundred ninety-two thousand, eight hundred seven".