Base | Representation |
---|---|
bin | 10010011000100001011001… |
… | …101111111011001001101111 |
3 | 101121021011220102120121222101 |
4 | 102120201121233323021233 |
5 | 41044121214322141213 |
6 | 443541544041555531 |
7 | 23013134425646353 |
oct | 2230413157731157 |
9 | 347234812517871 |
10 | 80849970115183 |
11 | 23841309414a95 |
12 | 90993234a5ba7 |
13 | 3616172616b89 |
14 | 15d72336ab463 |
15 | 95315eb6abdd |
hex | 498859bfb26f |
80849970115183 has 2 divisors, whose sum is σ = 80849970115184. Its totient is φ = 80849970115182.
The previous prime is 80849970115129. The next prime is 80849970115237. The reversal of 80849970115183 is 38151107994808.
It is a balanced prime because it is at equal distance from previous prime (80849970115129) and next prime (80849970115237).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-80849970115183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (80849970115583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40424985057591 + 40424985057592.
It is an arithmetic number, because the mean of its divisors is an integer number (40424985057592).
Almost surely, 280849970115183 is an apocalyptic number.
80849970115183 is a deficient number, since it is larger than the sum of its proper divisors (1).
80849970115183 is an equidigital number, since it uses as much as digits as its factorization.
80849970115183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17418240, while the sum is 64.
The spelling of 80849970115183 in words is "eighty trillion, eight hundred forty-nine billion, nine hundred seventy million, one hundred fifteen thousand, one hundred eighty-three".
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