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811275572117 is a prime number
BaseRepresentation
bin10111100111000111100…
…10101101001110010101
32212120001012010011002202
423303203302231032111
5101242443021301432
61420410031014245
7112420110404063
oct13634362551625
92776035104082
10811275572117
11293072a01a3a
1211129266a385
135b66cccb13a
142b3a1a8b033
1516183167462
hexbce3cad395

811275572117 has 2 divisors, whose sum is σ = 811275572118. Its totient is φ = 811275572116.

The previous prime is 811275572111. The next prime is 811275572119. The reversal of 811275572117 is 711275572118.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 811222661041 + 52911076 = 900679^2 + 7274^2 .

It is a cyclic number.

It is not a de Polignac number, because 811275572117 - 224 = 811258794901 is a prime.

Together with 811275572119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (811275572111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405637786058 + 405637786059.

It is an arithmetic number, because the mean of its divisors is an integer number (405637786059).

Almost surely, 2811275572117 is an apocalyptic number.

It is an amenable number.

811275572117 is a deficient number, since it is larger than the sum of its proper divisors (1).

811275572117 is an equidigital number, since it uses as much as digits as its factorization.

811275572117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 274400, while the sum is 47.

Subtracting from 811275572117 its reverse (711275572118), we obtain a palindrome (99999999999).

The spelling of 811275572117 in words is "eight hundred eleven billion, two hundred seventy-five million, five hundred seventy-two thousand, one hundred seventeen".