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81353720133470 = 2546317570997869
BaseRepresentation
bin10010011111110110100011…
…100101101111011101011110
3101200001100011122010000020002
4102133312203211233131132
541130344404323232340
6445005214425054302
723064420011314661
oct2237664345573536
9350040148100202
1081353720133470
1123a15a12145754
12915aa90327392
13365181364c085
1416137809716d8
159612e4ae5715
hex49fda396f75e

81353720133470 has 16 divisors (see below), whose sum is σ = 146752974210240. Its totient is φ = 32471204060064.

The previous prime is 81353720133463. The next prime is 81353720133481. The reversal of 81353720133470 is 7433102735318.

It is a super-3 number, since 3×813537201334703 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8785494305 + ... + 8785503564.

It is an arithmetic number, because the mean of its divisors is an integer number (9172060888140).

Almost surely, 281353720133470 is an apocalyptic number.

81353720133470 is a deficient number, since it is larger than the sum of its proper divisors (65399254076770).

81353720133470 is a wasteful number, since it uses less digits than its factorization.

81353720133470 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17570998339.

The product of its (nonzero) digits is 1270080, while the sum is 47.

Adding to 81353720133470 its reverse (7433102735318), we get a palindrome (88786822868788).

The spelling of 81353720133470 in words is "eighty-one trillion, three hundred fifty-three billion, seven hundred twenty million, one hundred thirty-three thousand, four hundred seventy".

Divisors: 1 2 5 10 463 926 2315 4630 17570997869 35141995738 87854989345 175709978690 8135372013347 16270744026694 40676860066735 81353720133470