Base | Representation |
---|---|
bin | 100110101101100110… |
… | …0001111100000110111 |
3 | 21221120202212202021002 |
4 | 1031123030033200313 |
5 | 2330224341031201 |
6 | 102105200513515 |
7 | 6002101004621 |
oct | 1153314174067 |
9 | 257522782232 |
10 | 83134314551 |
11 | 32291175a92 |
12 | 1414161b89b |
13 | 7abb5b5902 |
14 | 4049145c11 |
15 | 226874476b |
hex | 135b30f837 |
83134314551 has 2 divisors, whose sum is σ = 83134314552. Its totient is φ = 83134314550.
The previous prime is 83134314547. The next prime is 83134314581. The reversal of 83134314551 is 15541343138.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 83134314551 - 22 = 83134314547 is a prime.
It is a super-2 number, since 2×831343145512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (83134314521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 41567157275 + 41567157276.
It is an arithmetic number, because the mean of its divisors is an integer number (41567157276).
Almost surely, 283134314551 is an apocalyptic number.
83134314551 is a deficient number, since it is larger than the sum of its proper divisors (1).
83134314551 is an equidigital number, since it uses as much as digits as its factorization.
83134314551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86400, while the sum is 38.
Adding to 83134314551 its reverse (15541343138), we get a palindrome (98675657689).
The spelling of 83134314551 in words is "eighty-three billion, one hundred thirty-four million, three hundred fourteen thousand, five hundred fifty-one".
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