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955443642317 is a prime number
BaseRepresentation
bin11011110011101001110…
…00001111111111001101
310101100011111202221021022
431321310320033333031
5111123222033023232
62010531425043525
7126012532650413
oct15716470177715
93340144687238
10955443642317
1133922403399a
121352081865a5
136c137269658
143435aa9d2b3
1519cbec5c812
hexde74e0ffcd

955443642317 has 2 divisors, whose sum is σ = 955443642318. Its totient is φ = 955443642316.

The previous prime is 955443642287. The next prime is 955443642319. The reversal of 955443642317 is 713246344559.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 906511547881 + 48932094436 = 952109^2 + 221206^2 .

It is a cyclic number.

It is not a de Polignac number, because 955443642317 - 28 = 955443642061 is a prime.

Together with 955443642319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (955443642319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 477721821158 + 477721821159.

It is an arithmetic number, because the mean of its divisors is an integer number (477721821159).

Almost surely, 2955443642317 is an apocalyptic number.

It is an amenable number.

955443642317 is a deficient number, since it is larger than the sum of its proper divisors (1).

955443642317 is an equidigital number, since it uses as much as digits as its factorization.

955443642317 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10886400, while the sum is 53.

The spelling of 955443642317 in words is "nine hundred fifty-five billion, four hundred forty-three million, six hundred forty-two thousand, three hundred seventeen".