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991011013319 is a prime number
BaseRepresentation
bin11100110101111001101…
…11000000001011000111
310111201222021001120220102
432122330313000023013
5112214042304411234
62035133021154315
7131412114424535
oct16327467001307
93451867046812
10991011013319
11352315977188
121400936bb99b
13725b4ba3402
1435d7269b155
151aba2512c7e
hexe6bcdc02c7

991011013319 has 2 divisors, whose sum is σ = 991011013320. Its totient is φ = 991011013318.

The previous prime is 991011013301. The next prime is 991011013357. The reversal of 991011013319 is 913310110199.

It is an a-pointer prime, because the next prime (991011013357) can be obtained adding 991011013319 to its sum of digits (38).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 991011013319 - 28 = 991011013063 is a prime.

It is a super-2 number, since 2×9910110133192 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (991011013819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 495505506659 + 495505506660.

It is an arithmetic number, because the mean of its divisors is an integer number (495505506660).

Almost surely, 2991011013319 is an apocalyptic number.

991011013319 is a deficient number, since it is larger than the sum of its proper divisors (1).

991011013319 is an equidigital number, since it uses as much as digits as its factorization.

991011013319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6561, while the sum is 38.

The spelling of 991011013319 in words is "nine hundred ninety-one billion, eleven million, thirteen thousand, three hundred nineteen".