Base | Representation |
---|---|
bin | 101110001010000011… |
… | …0111101001110000111 |
3 | 100110211221210210120202 |
4 | 1130110012331032013 |
5 | 3111000113201001 |
6 | 113311424121115 |
7 | 10106216555324 |
oct | 1342406751607 |
9 | 313757723522 |
10 | 99121615751 |
11 | 39045628004 |
12 | 1726376619b |
13 | 9468843a52 |
14 | 4b2452db4b |
15 | 28a207c96b |
hex | 17141bd387 |
99121615751 has 2 divisors, whose sum is σ = 99121615752. Its totient is φ = 99121615750.
The previous prime is 99121615687. The next prime is 99121615753. The reversal of 99121615751 is 15751612199.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 99121615751 - 26 = 99121615687 is a prime.
Together with 99121615753, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 99121615696 and 99121615705.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99121615753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49560807875 + 49560807876.
It is an arithmetic number, because the mean of its divisors is an integer number (49560807876).
Almost surely, 299121615751 is an apocalyptic number.
99121615751 is a deficient number, since it is larger than the sum of its proper divisors (1).
99121615751 is an equidigital number, since it uses as much as digits as its factorization.
99121615751 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 170100, while the sum is 47.
The spelling of 99121615751 in words is "ninety-nine billion, one hundred twenty-one million, six hundred fifteen thousand, seven hundred fifty-one".
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