Base | Representation |
---|---|
bin | 101110001100111100… |
… | …0001110011010010111 |
3 | 100111002200221211100102 |
4 | 1130121320032122113 |
5 | 3111144403323203 |
6 | 113325203004315 |
7 | 10111503426515 |
oct | 1343170163227 |
9 | 314080854312 |
10 | 99218417303 |
11 | 39095234495 |
12 | 1729006969b |
13 | 9482907785 |
14 | 4b3332b4b5 |
15 | 28aa7ee888 |
hex | 1719e0e697 |
99218417303 has 2 divisors, whose sum is σ = 99218417304. Its totient is φ = 99218417302.
The previous prime is 99218417227. The next prime is 99218417321. The reversal of 99218417303 is 30371481299.
It is a strong prime.
It is an emirp because it is prime and its reverse (30371481299) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 99218417303 - 212 = 99218413207 is a prime.
It is a super-2 number, since 2×992184173032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (99218417323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49609208651 + 49609208652.
It is an arithmetic number, because the mean of its divisors is an integer number (49609208652).
Almost surely, 299218417303 is an apocalyptic number.
99218417303 is a deficient number, since it is larger than the sum of its proper divisors (1).
99218417303 is an equidigital number, since it uses as much as digits as its factorization.
99218417303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 47.
The spelling of 99218417303 in words is "ninety-nine billion, two hundred eighteen million, four hundred seventeen thousand, three hundred three".
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