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99218417321 is a prime number
BaseRepresentation
bin101110001100111100…
…0001110011010101001
3100111002200221211101002
41130121320032122221
53111144403323241
6113325203004345
710111503426542
oct1343170163251
9314080854332
1099218417321
1139095234501
12172900696b5
13948290779a
144b3332b4c9
1528aa7ee89b
hex1719e0e6a9

99218417321 has 2 divisors, whose sum is σ = 99218417322. Its totient is φ = 99218417320.

The previous prime is 99218417303. The next prime is 99218417323. The reversal of 99218417321 is 12371481299.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51284131600 + 47934285721 = 226460^2 + 218939^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-99218417321 is a prime.

It is a super-2 number, since 2×992184173212 (a number of 23 digits) contains 22 as substring.

Together with 99218417323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (99218417323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49609208660 + 49609208661.

It is an arithmetic number, because the mean of its divisors is an integer number (49609208661).

Almost surely, 299218417321 is an apocalyptic number.

It is an amenable number.

99218417321 is a deficient number, since it is larger than the sum of its proper divisors (1).

99218417321 is an equidigital number, since it uses as much as digits as its factorization.

99218417321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 217728, while the sum is 47.

The spelling of 99218417321 in words is "ninety-nine billion, two hundred eighteen million, four hundred seventeen thousand, three hundred twenty-one".