994793312520000 has 3920 divisors, whose sum is σ = 4365319088739840. Its totient is φ = 220043132928000.

The previous prime is 994793312519899. The next prime is 994793312520017. The reversal of 994793312520000 is 25213397499.

994793312520000 is a `hidden beast` number, since 9 + 9 + 4 + 79 + 33 + 12 + 520 + 0 + 0 + 0 = 666.

It is a super-2 number, since 2×994793312520000² (a number of 31 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (54).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 559 ways as a sum of consecutive naturals, for example, 930583079466 + ... + 930583080534.

It is an arithmetic number, because the mean of its divisors is an integer number (1113601808352).

Almost surely, 2^{994793312520000} is an apocalyptic number.

994793312520000 is a gapful number since it is divisible by the number (90) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 994793312520000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2182659544369920).

994793312520000 is an abundant number, since it is smaller than the sum of its proper divisors (3370525776219840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

994793312520000 is an equidigital number, since it uses as much as digits as its factorization.

994793312520000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1270 (or 1230 counting only the distinct ones).

The product of its (nonzero) digits is 3674160, while the sum is 54.

The spelling of 994793312520000 in words is "nine hundred ninety-four trillion, seven hundred ninety-three billion, three hundred twelve million, five hundred twenty thousand".