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9972518471 is a prime number
BaseRepresentation
bin10010100100110100…
…01000111001000111
3221202000001102112222
421102122020321013
5130410431042341
64325321402555
7502062002606
oct112232107107
927660042488
109972518471
114258254803
121b2393945b
13c2c0b7906
146a864ba3d
153d578044b
hex252688e47

9972518471 has 2 divisors, whose sum is σ = 9972518472. Its totient is φ = 9972518470.

The previous prime is 9972518459. The next prime is 9972518473. The reversal of 9972518471 is 1748152799.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 9972518471 - 214 = 9972502087 is a prime.

It is a super-3 number, since 3×99725184713 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 9972518473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9972518473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4986259235 + 4986259236.

It is an arithmetic number, because the mean of its divisors is an integer number (4986259236).

Almost surely, 29972518471 is an apocalyptic number.

9972518471 is a deficient number, since it is larger than the sum of its proper divisors (1).

9972518471 is an equidigital number, since it uses as much as digits as its factorization.

9972518471 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1270080, while the sum is 53.

The square root of 9972518471 is about 99862.4978207535. The cubic root of 9972518471 is about 2152.4593073937.

The spelling of 9972518471 in words is "nine billion, nine hundred seventy-two million, five hundred eighteen thousand, four hundred seventy-one".