1000113140100 has 72 divisors (see below), whose sum is σ = 2901858331680. Its totient is φ = 265941294080.

The previous prime is 1000113140093. The next prime is 1000113140101. The reversal of 1000113140100 is 10413110001.

1000113140100 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (1000113140101) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4616070 + ... + 4827869.

It is an arithmetic number, because the mean of its divisors is an integer number (40303587940).

Almost surely, 2^{1000113140100} is an apocalyptic number.

1000113140100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1000113140100 is an abundant number, since it is smaller than the sum of its proper divisors (1901745191580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1000113140100 is a wasteful number, since it uses less digits than its factorization.

1000113140100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9444309 (or 9444302 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 1000113140100 its reverse (10413110001), we get a palindrome (1010526250101).

The spelling of 1000113140100 in words is "one trillion, one hundred thirteen million, one hundred forty thousand, one hundred".