1004344120130 has 48 divisors (see below), whose sum is σ = 2068141640040. Its totient is φ = 349020930048.

The previous prime is 1004344120121. The next prime is 1004344120217. The reversal of 1004344120130 is 310214434001.

1004344120130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 12 ways, for example, as 270825527281 + 733518592849 = 520409^2 + 856457^2 .

It is a super-3 number, since 3×1004344120130³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1004344120096 and 1004344120105.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 13328735 + ... + 13403874.

Almost surely, 2^{1004344120130} is an apocalyptic number.

1004344120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1004344120130 is an abundant number, since it is smaller than the sum of its proper divisors (1063797519910).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1004344120130 is a wasteful number, since it uses less digits than its factorization.

1004344120130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26732663 (or 26732646 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1004344120130 its reverse (310214434001), we get a palindrome (1314558554131).

The spelling of 1004344120130 in words is "one trillion, four billion, three hundred forty-four million, one hundred twenty thousand, one hundred thirty".