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10053120000 = 21235471117
BaseRepresentation
bin10010101110011011…
…00111000000000000
3221221121201102001210
421113031213000000
5131042044320000
64341321130120
7504061052520
oct112715470000
927847642053
1010053120000
1142997a6940
121b46929940
13c429c8a21
146b522d680
153dc8a2350
hex257367000

10053120000 has 1040 divisors, whose sum is σ = 44217245952. Its totient is φ = 1966080000.

The previous prime is 10053119981. The next prime is 10053120013. The reversal of 10053120000 is 2135001.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 591359992 + ... + 591360008.

Almost surely, 210053120000 is an apocalyptic number.

10053120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 10053120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22108622976).

10053120000 is an abundant number, since it is smaller than the sum of its proper divisors (34164125952).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10053120000 is an equidigital number, since it uses as much as digits as its factorization.

10053120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82 (or 45 counting only the distinct ones).

The product of its (nonzero) digits is 30, while the sum is 12.

Adding to 10053120000 its reverse (2135001), we get a palindrome (10055255001).

The spelling of 10053120000 in words is "ten billion, fifty-three million, one hundred twenty thousand".