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1010001113357 is a prime number
BaseRepresentation
bin11101011001010001100…
…00011111000100001101
310120112222201021121211212
432230220300133010031
5113021440241111412
62051553233024205
7132653524545635
oct16545060370415
93515881247755
101010001113357
1135a380330435
121438b33b5065
13743202859b2
1436c547b96c5
151b414794222
hexeb28c1f10d

1010001113357 has 2 divisors, whose sum is σ = 1010001113358. Its totient is φ = 1010001113356.

The previous prime is 1010001113333. The next prime is 1010001113369. The reversal of 1010001113357 is 7533111000101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1004908007401 + 5093105956 = 1002451^2 + 71366^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1010001113357 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010001113557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505000556678 + 505000556679.

It is an arithmetic number, because the mean of its divisors is an integer number (505000556679).

Almost surely, 21010001113357 is an apocalyptic number.

It is an amenable number.

1010001113357 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010001113357 is an equidigital number, since it uses as much as digits as its factorization.

1010001113357 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 315, while the sum is 23.

Adding to 1010001113357 its reverse (7533111000101), we get a palindrome (8543112113458).

The spelling of 1010001113357 in words is "one trillion, ten billion, one million, one hundred thirteen thousand, three hundred fifty-seven".