10103157131 has 2 divisors, whose sum is σ = 10103157132. Its totient is φ = 10103157130.

The previous prime is 10103157073. The next prime is 10103157133. The reversal of 10103157131 is 13175130101.

It is a happy number.

10103157131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10103157131 - 2⁶ = 10103157067 is a prime.

It is a super-2 number, since 2×10103157131² (a number of 21 digits) contains 22 as substring.

Together with 10103157133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10103157097 and 10103157106.

It is not a weakly prime, because it can be changed into another prime (10103157133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5051578565 + 5051578566.

It is an arithmetic number, because the mean of its divisors is an integer number (5051578566).

Almost surely, 2^10103157131 is an apocalyptic number.

10103157131 is a deficient number, since it is larger than the sum of its proper divisors (1).

10103157131 is an equidigital number, since it uses as much as digits as its factorization.

10103157131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 315, while the sum is 23.

Adding to 10103157131 its reverse (13175130101), we get a palindrome (23278287232).

The spelling of 10103157131 in words is "ten billion, one hundred three million, one hundred fifty-seven thousand, one hundred thirty-one".