Base | Representation |
---|---|
bin | 11101011011100000011… |
… | …10010111110100011010 |
3 | 10120200002021102222220220 |
4 | 32231300032113310122 |
5 | 113031414213132310 |
6 | 2052312224100510 |
7 | 133025324201145 |
oct | 16556016276432 |
9 | 3520067388826 |
10 | 1011200130330 |
11 | 35a936125655 |
12 | 143b88a64736 |
13 | 744817c48b0 |
14 | 36d29b3105c |
15 | 1b484b88670 |
hex | eb70397d1a |
1011200130330 has 64 divisors (see below), whose sum is σ = 2669171194368. Its totient is φ = 243614822400.
The previous prime is 1011200130307. The next prime is 1011200130331. The reversal of 1011200130330 is 330310021101.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is not an unprimeable number, because it can be changed into a prime (1011200130331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27564871 + ... + 27601530.
It is an arithmetic number, because the mean of its divisors is an integer number (41705799912).
Almost surely, 21011200130330 is an apocalyptic number.
1011200130330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1011200130330 is an abundant number, since it is smaller than the sum of its proper divisors (1657971064038).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1011200130330 is a wasteful number, since it uses less digits than its factorization.
1011200130330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55166471.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 1011200130330 its reverse (330310021101), we get a palindrome (1341510151431).
The spelling of 1011200130330 in words is "one trillion, eleven billion, two hundred million, one hundred thirty thousand, three hundred thirty".
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