101121120010021 has 2 divisors, whose sum is σ = 101121120010022. Its totient is φ = 101121120010020.

The previous prime is 101121120010019. The next prime is 101121120010073. The reversal of 101121120010021 is 120010021121101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87772802013796 + 13348317996225 = 9368714^2 + 3653535^2 .

It is an emirp because it is prime and its reverse (120010021121101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101121120010021 - 2¹ = 101121120010019 is a prime.

Together with 101121120010019, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 101121120009983 and 101121120010010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101121120019021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50560560005010 + 50560560005011.

It is an arithmetic number, because the mean of its divisors is an integer number (50560560005011).

Almost surely, 2^{101121120010021} is an apocalyptic number.

It is an amenable number.

101121120010021 is a deficient number, since it is larger than the sum of its proper divisors (1).

101121120010021 is an equidigital number, since it uses as much as digits as its factorization.

101121120010021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 101121120010021 its reverse (120010021121101), we get a palindrome (221131141131122).

The spelling of 101121120010021 in words is "one hundred one trillion, one hundred twenty-one billion, one hundred twenty million, ten thousand, twenty-one".