10113543341 has 8 divisors (see below), whose sum is σ = 11033725824. Its totient is φ = 9193489120.

The previous prime is 10113543337. The next prime is 10113543343. The reversal of 10113543341 is 14334531101.

10113543341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10113543341 - 2² = 10113543337 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 10113543341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113543343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 216881 + ... + 259353.

It is an arithmetic number, because the mean of its divisors is an integer number (1379215728).

Almost surely, 2^10113543341 is an apocalyptic number.

10113543341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

10113543341 is a deficient number, since it is larger than the sum of its proper divisors (920182483).

10113543341 is a wasteful number, since it uses less digits than its factorization.

10113543341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64131.

The product of its (nonzero) digits is 2160, while the sum is 26.

The spelling of 10113543341 in words is "ten billion, one hundred thirteen million, five hundred forty-three thousand, three hundred forty-one".