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10202221319 is a prime number
BaseRepresentation
bin10011000000001100…
…11000101100000111
3222100000021112121212
421200012120230013
5131343232040234
64404205002035
7510551310323
oct114006305407
928300245555
1010202221319
114365984974
121b8885331b
13c67871864
146cad62983
153eaa055ce
hex260198b07

10202221319 has 2 divisors, whose sum is σ = 10202221320. Its totient is φ = 10202221318.

The previous prime is 10202221301. The next prime is 10202221321. The reversal of 10202221319 is 91312220201.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (91312220201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10202221319 - 28 = 10202221063 is a prime.

It is a super-2 number, since 2×102022213192 (a number of 21 digits) contains 22 as substring.

Together with 10202221321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10202221294 and 10202221303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10202221219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5101110659 + 5101110660.

It is an arithmetic number, because the mean of its divisors is an integer number (5101110660).

Almost surely, 210202221319 is an apocalyptic number.

10202221319 is a deficient number, since it is larger than the sum of its proper divisors (1).

10202221319 is an equidigital number, since it uses as much as digits as its factorization.

10202221319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

The spelling of 10202221319 in words is "ten billion, two hundred two million, two hundred twenty-one thousand, three hundred nineteen".