Base | Representation |
---|---|
bin | 10011000011101001… |
… | …00110011001010100 |
3 | 222102000122101222020 |
4 | 21201310212121110 |
5 | 131423131111200 |
6 | 4411120133140 |
7 | 511352012442 |
oct | 114164463124 |
9 | 28360571866 |
10 | 10231113300 |
11 | 4380218941 |
12 | 1b964671b0 |
13 | c708493c5 |
14 | 6d0b23b92 |
15 | 3ed310ea0 |
hex | 261d26654 |
10231113300 has 72 divisors (see below), whose sum is σ = 30103802400. Its totient is φ = 2682049920.
The previous prime is 10231113289. The next prime is 10231113313. The reversal of 10231113300 is 331113201.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 10231113300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 271315 + ... + 306714.
Almost surely, 210231113300 is an apocalyptic number.
10231113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
10231113300 is an abundant number, since it is smaller than the sum of its proper divisors (19872689100).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
10231113300 is a wasteful number, since it uses less digits than its factorization.
10231113300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 578105 (or 578098 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 10231113300 its reverse (331113201), we get a palindrome (10562226501).
Subtracting from 10231113300 its reverse (331113201), we obtain a palindrome (9900000099).
The spelling of 10231113300 in words is "ten billion, two hundred thirty-one million, one hundred thirteen thousand, three hundred".
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