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103130202131132 = 22112213078930023
BaseRepresentation
bin10111011100101111011111…
…000100000100101010111100
3111112011011002002212101010212
4113130233133010010222330
5102004141123221144012
61003201205533451552
730502624356225311
oct2734573704045274
9445134062771125
10103130202131132
112a951300560100
12b6973a8040bb8
1345711a069c997
141b67757d8cd08
15bdc9be9a2b22
hex5dcbdf104abc

103130202131132 has 18 divisors (see below), whose sum is σ = 198376483852344. Its totient is φ = 46877364604840.

The previous prime is 103130202131093. The next prime is 103130202131153. The reversal of 103130202131132 is 231131202031301.

It is a super-3 number, since 3×1031302021311323 (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103130202131098 and 103130202131107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 106539464528 + ... + 106539465495.

Almost surely, 2103130202131132 is an apocalyptic number.

It is an amenable number.

103130202131132 is a deficient number, since it is larger than the sum of its proper divisors (95246281721212).

103130202131132 is a wasteful number, since it uses less digits than its factorization.

103130202131132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 213078930049 (or 213078930036 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 103130202131132 its reverse (231131202031301), we get a palindrome (334261404162433).

The spelling of 103130202131132 in words is "one hundred three trillion, one hundred thirty billion, two hundred two million, one hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 11 22 44 121 242 484 213078930023 426157860046 852315720092 2343868230253 4687736460506 9375472921012 25782550532783 51565101065566 103130202131132