Base | Representation |
---|---|
bin | 11110101011010001100… |
… | …11011011110100110100 |
3 | 10201202121211120002102020 |
4 | 33111220303123310310 |
5 | 114232120434120200 |
6 | 2124113524113140 |
7 | 136102505144046 |
oct | 17255063336464 |
9 | 3652554502366 |
10 | 1054025301300 |
11 | 377011893434 |
12 | 15033ab357b0 |
13 | 78517c7834a |
14 | 3902d5d5a96 |
15 | 1c63e6ccea0 |
hex | f568cdbd34 |
1054025301300 has 72 divisors (see below), whose sum is σ = 3099640797792. Its totient is φ = 276465648000.
The previous prime is 1054025301209. The next prime is 1054025301317. The reversal of 1054025301300 is 31035204501.
It is a super-2 number, since 2×10540253013002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 28780206 + ... + 28816805.
It is an arithmetic number, because the mean of its divisors is an integer number (43050566636).
Almost surely, 21054025301300 is an apocalyptic number.
1054025301300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1054025301300 is an abundant number, since it is smaller than the sum of its proper divisors (2045615496492).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1054025301300 is a wasteful number, since it uses less digits than its factorization.
1054025301300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57597089 (or 57597082 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 24.
The spelling of 1054025301300 in words is "one trillion, fifty-four billion, twenty-five million, three hundred one thousand, three hundred".
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