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1100000051 is a prime number
BaseRepresentation
bin100000110010000…
…1010101100110011
32211122211210101122
41001210022230303
54223100000201
6301052452455
736154563143
oct10144125463
92748753348
101100000051
11514a15357
1226847a12b
13146b80a07
14a613c923
1566885e1b
hex4190ab33

1100000051 has 2 divisors, whose sum is σ = 1100000052. Its totient is φ = 1100000050.

The previous prime is 1100000017. The next prime is 1100000059. The reversal of 1100000051 is 1500000011.

It is a happy number.

It is an a-pointer prime, because the next prime (1100000059) can be obtained adding 1100000051 to its sum of digits (8).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100000051 - 214 = 1099983667 is a prime.

It is a super-2 number, since 2×11000000512 = 2420000224400005202, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1099999984 and 1100000038.

It is not a weakly prime, because it can be changed into another prime (1100000059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000025 + 550000026.

It is an arithmetic number, because the mean of its divisors is an integer number (550000026).

Almost surely, 21100000051 is an apocalyptic number.

1100000051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100000051 is an equidigital number, since it uses as much as digits as its factorization.

1100000051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5, while the sum is 8.

The square root of 1100000051 is about 33166.2486724079. The cubic root of 1100000051 is about 1032.2801314098.

Adding to 1100000051 its reverse (1500000011), we get a palindrome (2600000062).

The spelling of 1100000051 in words is "one billion, one hundred million, fifty-one", and thus it is an aban number.