110010000000079 has 2 divisors, whose sum is σ = 110010000000080. Its totient is φ = 110010000000078.

The previous prime is 110010000000067. The next prime is 110010000000091. The reversal of 110010000000079 is 970000000010011.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (110010000000067) and next prime (110010000000091).

It is an emirp because it is prime and its reverse (970000000010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110010000000079 - 2²⁷ = 110009865782351 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110009999999993 and 110010000000065.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010000000379) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005000000039 + 55005000000040.

It is an arithmetic number, because the mean of its divisors is an integer number (55005000000040).

Almost surely, 2^{110010000000079} is an apocalyptic number.

110010000000079 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010000000079 is an equidigital number, since it uses as much as digits as its factorization.

110010000000079 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 19.

The spelling of 110010000000079 in words is "one hundred ten trillion, ten billion, seventy-nine", and thus it is an aban number.